Explain why hypophophorous acid acts as reducing agent but phosphoric …
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작성자 Deangelo 작성일 25-01-15 19:37 조회 27 댓글 0본문
H3PO4, phosphorous acid, is the most stable form of a __phosphor___ acid
In H3PO4 H3 = +3, P = __ O4 = -8
In H3PO4 the charge on P = +5
The 4 O atoms have attracted 5 electrons from the P atom.
These were the 3s2, 3p3 electrons, leaving the P atom with 2s2, sp8, an octet, a stable state.
Hypophosphoric acid = H3PO2
In H3PO2, H3 =+3, P = ___, O2 = -4
In H3PO2, the charge on P = +1
One of the O atoms has attracted 1 electron from the P atom.
This electron came from were the 3s2, 3p3 electrons, leaving the P atom with 3s2, 3p2 an unstable state.
The P atom in H3PO2 needs to lose the 4 electrons, 3s2, 3p2, to be stable. This means the H3PO2 is oxidized, as it reduces a nonmetal such as I2.
Phosphoric acid removes the zinc coating from roofing nails. It is an ingredient in Toilet bowl cleaner.
The reaction equation is ;
Zn + H3PO4 à + Zn3(PO4)2 + H2
Zn = 0 charge is oxidized to Zn +2 charge in the Zn3(PO4)2; as H+1 charge in the H3(PO4)3 is reduced to H = 0 charge in H2. The H2 is the oxidizing agent, and the Zn is the reducing agent.
The H in the Phosphoric acid causes Zinc to be oxidized from Zn = 0 charge to Zn = +2 charge. Thus Phosphoric acid provides an oxidizing agent.
In H3PO4 H3 = +3, P = __ O4 = -8
In H3PO4 the charge on P = +5
The 4 O atoms have attracted 5 electrons from the P atom.
These were the 3s2, 3p3 electrons, leaving the P atom with 2s2, sp8, an octet, a stable state.
Hypophosphoric acid = H3PO2
In H3PO2, H3 =+3, P = ___, O2 = -4
In H3PO2, the charge on P = +1
One of the O atoms has attracted 1 electron from the P atom.
This electron came from were the 3s2, 3p3 electrons, leaving the P atom with 3s2, 3p2 an unstable state.
The P atom in H3PO2 needs to lose the 4 electrons, 3s2, 3p2, to be stable. This means the H3PO2 is oxidized, as it reduces a nonmetal such as I2.
Phosphoric acid removes the zinc coating from roofing nails. It is an ingredient in Toilet bowl cleaner.
The reaction equation is ;
Zn + H3PO4 à + Zn3(PO4)2 + H2
Zn = 0 charge is oxidized to Zn +2 charge in the Zn3(PO4)2; as H+1 charge in the H3(PO4)3 is reduced to H = 0 charge in H2. The H2 is the oxidizing agent, and the Zn is the reducing agent.
The H in the Phosphoric acid causes Zinc to be oxidized from Zn = 0 charge to Zn = +2 charge. Thus Phosphoric acid provides an oxidizing agent.
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